Acid/Base Titration

(Titration of a base with an acid)


Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide

CH3COOH (aq) + NaOH (aq) -----> Na+(aq) + CH3COOH-(aq) + H2O (l)


  1. Figure out how many moles of the titrant (in this case, the base) were needed.

    (25.19 mL) (1 L/ 1000 mL) = 0.02519 L

    0.02519 L) (0.1025 mol / L) = 0.002582 mol NaOH

  2. Use the balanced chemical equation to calculate the moles of analyte (in this case, the acid) present.

    (0.002582 mol NaOH) (1 mol CH3COOH / 1 mol NaOH) = 0.002582 mol CH3COOH

  3. Use the volume of analyte to find the concentration of the analyte.

Previous Step Next Step

Stoichiometry Problems Problem Solving General Chemistry Help Homepage