Practice Problem 4
Which of the following is the strongest oxidizing agent?
(a) H2O2 in acid
(b) H2O2 in base
(c) MnO4- in acid
(d) MnO4- in base
(e) CrO42- in acid
We start by searching the table of standard-state reduction potentials for the reduction half-cell potential for the oxidizing agent in each of these solutions.
|(a) H2O2 + 2 H+ + 2 e- 2 H2O||Eored = 1.776 V|
|(b) H2O2 + 2 e- 2 OH-||Eored = 0.88 V|
|(c) MnO4- + 8 H+ + 5 e- Mn2+ + 4 H2O||Eored = 1.491 V|
|(d) MnO4- + 2 H2O + 3 e- MnO2 + 4 OH-||Eored = 0.588 V|
|(e) CrO42- + 8 H+ + 3 e- Cr3+ + 4 H2O||Eored = 1.195|
According to these data, the strongest oxidizing agent is H2O2 in acid.