Acid/Base Titration

(Titration of a base with an acid)

Problem:

Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide

CH3COOH (aq) + NaOH (aq) -----> Na+(aq) + CH3COOH-(aq) + H2O (l)

Strategy:

  1. Figure out how many moles of the titrant (in this case, the base) were needed.

    (25.19 mL) (1L/1000 mL) = 0.02519 L

    (0.02519 L) (0.1025 mol / L) = 0.002582 mol NaOH

     

  2. Use the balanced chemical equation to calculate the moles of analyte (in this case, the acid) present.

  3. Use the volume of analyte to find the concentration of the analyte.


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