**Practice Problem 5**

Ammonia is made from nitrogen and hydrogen by the following reversible reaction.

N_{2}(*g*) + 3 H_{2}(*g*) 2 NH_{3}(*g*)

Assume that the initial concentration of N_{2} is
0.050 moles per liter and the initial concentration of H_{2}
is 0.100 moles per liter. Calculate the equilibrium
concentrations of the three components of this reaction at 500^{o}C
if the equilibrium constant for the reaction at this temperature
is 0.040.

**Answer**

[NH_{3}] = 0.0020 *M*

[N_{2}] = 0.099 *M*

[H_{2}] = 0.097 *M*